Example: Impairment Test
This example uses the following initial data:
The asset is sold at the beginning of the year.
Consolidation Unit A (Seller) |
|
Consolidation Unit B (Buyer) |
|
Original value (acquisition cost) |
1000 |
Original value |
900 |
Beginning book value |
500 |
Beginning book value |
900 |
Ordinary
depreciation: |
0 |
Ordinary
depreciation: |
180 |
Ending book value |
0 |
Ending book value |
720 |
The current value equals 250 currency units.
Extraordinary depreciation (labeled “Ex.D” in the figure below) is calculated as follows:
Extraordinary depreciation = ending book valuebuyer – current value = 720 – 250 = 470
Total depreciation is calculated as follows:
Total depreciation = ordinary depreciation + extraordinary depreciation = 180 + 470 = 650
The depreciation adjustment solely based on the impairment test is calculated as follows:
Depreciation adjustment = 650 – (100 + 150) = 400
The amount of 150 is arrived at because the valuation of the group may not exceed the valuation of the buyer. Therefore, this part of the extraordinary depreciation must equal 150 to retain the group value of 250.

